General Tensor

Let us consider a general coordinate transformation:

x'a = x'a(x), a = 1….,n (1)

n is the dimension of space.

We have:

d x'a =
x'a
xb
d xb
(2)

In analogy with this we say that Va is a contravariant vector if under (1) it transforms like (2), i.e.

V'a(x') =
x'a
xb
Vb(x)
(3)

Similarly, let us consider the gradient of a scalar function. We say that A(x) is a scalar function if:A'(x') = A(x). It follows that:

A'(x')
x'a
=
A(x)
x'a
=
A(x)
xb
xb
x'a
(4)

In analogy with this transformation law, we say that Ua is a covariant vector if under a change of variables (1), we have:

U'a(x') =
xb
x'a
Ub(x)
(5)

Tensor Product

Consider two covariant vectors, Ua,Va. We have:

U'a(x')V'b(x') =
xc
x'a
xd
x'b
Uc(x)Vd(x)
(6)

We say that a set of functions Tab that transforms under (1) as (6) is a covariant tensor of rank 2. That is:

T'ab(x') =
xc
x'a
xd
x'b
Tcd(x)
(7)

We call Sab = UaVb the tensorial product of the two covariant vectors Ua and Vb.

Generally we says that a set of functions T

b1….bq
a1….ap
is a p-covariant and q-contravariant tensor if under (1) we have:

T'
b1….bq
a1….ap
(x') =
xc1
x'a1
….
xcp
x'ap
x'b1
xd1
….
x'bq
xdq
Tc1….cp d1….dq(x)
(8)

The tensor product of two arbitrary tensors U

b1….bq
a1….ap
,V
d1….ds
c1cr
defined by

U
b1….bq
a1….ap
(x)V
d1….ds
c1cr
(x)
(9)

is a (p+r) covariant and (q+s) contravariant tensor.

Contraction

Consider a mixed tensor T
b
a
, then

S = ∑na = 1T
a
a

is a scalar.

NOTATION(Einstein): Repeated indices in a monomial are summed from 1 to n.

Proof:

T '
a
a
( x ') =
x'a
xb
xc
x'a
T
b
c
( x ) = δ c b T
b
c
( x ) = T
b
b
( c )

In general the contraction of an upper index with a lower index in a p-covariant and q-contravariant tensor produces a (p-1) covariant and (q-1) contravariant tensor.

Notice that contraction of different indices, produces different tensors.

Some important tensors

Kronecker deltaab is a one covariant, one contravariant tensor. Moreover it is an invariant tensor, because it has the same components in all coordinate systems.

Proof:

δ'
b
a
=
x'b
x'a
=
x'b
xc
xc
xd
xd
x'a
=
x'b
xc
xd
x'a
δcd
(10)

Symmetric and antisymmetric tensors.

Consider Tcab a tensor. Then: Scab = Tcab + Tcba and Acab = Tcab - Tcba are tensors, called the symmetric and antisymmetric component of Tcab.

Proof:

S'cab(x') = T'cab(x') + T'cba(x') =
x'c
xi
xj
x'a
xk
x'b
Tijk(x) +
x'c
xi
xj
x'b
xk
x'a
Tijk(x) =
x'c
xi
xj
x'a
xk
x'b
(Tijk(x) + Tikj(x)) =
x'c
xi
xj
x'a
xk
x'b
Sijk(x)
(11)

The proof is similar for the antisymmetric part.Notice that this operation can be applied to any pair of indices. Iterative application of the operation will produce tensors that will form representations of the permutation group Sn

Pseudotensors

We define a pseudotensor of weight r a set of functions Db1….bqa1….ap that under (1) transform as follows:

D'
b1….bq
a1….ap
(x') = Jr
xc1
x'a1
….
xcp
x'ap
x'b1
xd1
….
x'bq
xdq
Dc1….cp d1….dq(x)
(12)

where J is the jacobian of the transformation (1). i.e.

J(x) = det(
xa
x'b
)
(13)

r=0, tensor

r=1, pseudotensor o tensor density

r=-1, tensor capacity

The Levi-Civita symbol

εa1….an = sgn(
1….n
a1an
)
(14)

Here sgn is the sign of the permutation in brackets. If some of the indices are repeated, it gives zero.

Use the determinant identity:

J - 1 sgn(σ) = ∑ λϵSn sgn(λ)
x'σ(1)
xλ(1)
….
x'σ(n)
xλ(n)

or

J - 1εa1….an =
x'a1
xb1
….
x'an)
xbn
εb1….bn
(15)

It follows that εa1….an is a pseudotensor of weight 1.

Similarly, we can prove that:

Jεa1….an =
x'b1
xa1
….
x'bn
xan
εb1….bn
(16)

so εa1….anis a pseudotensor of weight -1.

An important identity

We have that:

εj1….jnεi1….in = |
δi1j1….δi1jn
δi2j1….δi2jn
…………
δinj1….δinjn
|
(17)

Proof:

We must have: i1 = σ(1)….,in = σ(n) and j1 = λ(1),….jn = λ(n)for some permutations σ and λ, otherwise the determinant vanishes (either two columns or two rows are equal). Then, we get:

|
δi1j1….δi1jn
δi2j1….δi2jn
…………
δinj1….δinjn
| = sgn(σ)|
δ1j1….δ1jn
δ2j1….δ2jn
…………
δnj1….δnjn
| = sgn(σ)sgn(λ)|
δ11….δ1n
δ21….δ2n
…………
δn1….δnn
| = sgn(σ)sgn(λ) = ε j1….jn ε i1….in

Covariant Derivative

In cartesian coordinates, the partial derivative of a tensor is a tensor. This is no longer true in a general space. In order to define parallel transport we must provide for more structure.

We assume the space is provided with a set of n3 functions Γijk which transformation properties under (1) will be defined below:

Let Ai be a contravariant vector. We define the covariant derivative of Ai by:

Ai;j = Ai,j + ΓikjAk (18)

NOTATION: A i ,j =

Ai
xj

We want the covariant derivative to be a tensor under (1). That is:

A'i;j(x') =
x'i
xa
xb
x'j
Aa;b(x) =
x'i
xa
xb
x'j
(Aa,b + ΓakbAk)
= A'i,j + Γ'ikjA'k
= (
x'i
xa
Aa(x)),j + Γ'ikj(
x'k
xb
Ab(x))

comparing LHS and RHS, we get:

Γ'isk =
x'i
xm
xl
x'k
xh
x's
Γmhl -
2x'i
xlxh
xl
x'k
xh
x's
(19)

The set of quantities Γijk that transforms under (1) according to (19) is called an affine connection and the spaces provided with it, spaces with affine connection.

We postulate that the covariant derivative satisfies Leibnitz's rule:

(TS),k = T;kS + TS;k (20)

Consider Ai and Bj, then S = AiBi is a scalar. For a scalar, the covariant derivative coincides with the ordinary partial derivative. We have:

(AiBi);k = Ai;kBi + AiBi;k = (Ai,k + ΓijkAj)Bi + AiBi;k = Ai,kBi + AiBi,k

That is:

AijikBj + Bi;k - Bi,k) = 0

This is true for any Ai. It follows that:

Bi;k = Bi,k - ΓjikBj (21)

In general:

ti1….ipj1….jq;k = ti1….ipj1….jq,k + ∑
p
a = 1
Γiahkti1….h….ipj1….jq - ∑
q
a = 1
Γhjakti1….ipj1….ja - 1hjq
(22)

Torsion and Curvature

Let us consider a space with an affine connection Γ

We have:

Γijk - Γikj = Tijk (23)

T is a tensor, called the torsion tensor.

Additionally, consider:

ui;kl - ui;lk = tensor = Rijlkuj - Thklui;h (24)

where:

Rijlk = Γijk,l - Γijl,k + ΓhjkΓihl - ΓhjlΓihk (25)

is the curvature tensor.